Explanation:
Let us assume that mass of given sample is 894.0 g and temperature change is from [tex]-5.8^{o}C[/tex] to [tex]17.5^{o}C[/tex] and heat needed is 4.90 kJ (or 4900 J, as 1 kJ = 1000 J).
Therefore, calculate the heat capacity using the following formula.
Q = [tex]m \times C \times \Delta T[/tex]
[tex]4.90 \times 10^{3} J = 894.0 g \times C \times (17.5 - (-5.8)^{o}C[/tex]
[tex]4.90 \times 10^{3} J = 20830.2 g^{o}C \times C[/tex]
C = [tex]0.235 J/g^{o}C[/tex]
Therefore, we can conclude that specific heat capacity of the substance is [tex]0.235 J/g^{o}C[/tex].
