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The force required to stretch a Hooke’s-law spring varies from 0 N to 43.2 N as we stretch the spring by moving one end 14.4 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m.

Respuesta :

Answer:

Spring constant = 300 N/m

Explanation:

For a spring we have force is the product of spring constant and displacement.

          Force = Spring constant x Displacement

          F = k x

Here Force , F = 43.2 - 0 = 43.2 N

         Displacement, x = 14.4 cm = 0.144 m

Substituting

              F = k x

              43.2 = k x 0.144

               k= 300 N/m

Spring constant = 300 N/m

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