Respuesta :
Answer:
(a) Current will be [tex]17.857\times 10^{-12}A[/tex]
(b) Number of ions will be [tex]8.258\times 10^6[/tex]
Explanation:
We have given that resistance of the biological cell [tex]R=4.2\times 10^9ohm[/tex]
(a) We have given potential difference of 75 mV
So [tex]V=75\times 10^{-3}volt[/tex]
From ohm's law we know that current is given by
[tex]i=\frac{V}{R}=\frac{75\times 10^{-3}}{4.2\times 10^9}=17.857\times 10^{-12}A[/tex]
(b) We have given time t = 0.74 sec
We have to find the charge
We know that charge is given by Q = it, here i is current and t is time
So charge will be [tex]Q=17.857\times 10^{-12}\times 0.74=13.214\times 10^{-12}C[/tex]
So number of ions will be [tex]n=\frac{13.214\times 10^{-12}}{1.6\times 10^{-19}}=8.258\times 10^6[/tex]
