Respuesta :

nkirotedoreen46

Answer:

46.67 m/s²

Explanation:

We are given;

  • Mass of a rocket = 3 kg
  • Force applied = 140 N

we are supposed to calculate the acceleration of the rocket;

  • We are going to use the second Newton's law of motion;
  • According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
  • This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.

Therefore;

F = Ma

In this case;

Rearranging the formula

a = F ÷ m

  = 140 N ÷ 3 kg

  = 46.67 m/s²

Thus, the acceleration of the rocket is 46.67 m/s²

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