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What is the lift (in newtons) due to Bernoulli's principle on a wing of area 76 m2 if the air passes over the top and bottom surfaces at speeds of 290 m/s and 150 m/s, respectively? Express your answer to two significant figures and include the appropriate units.

Respuesta :

Answer:

So lift will be 30.19632 N

Explanation:

We have given area of the wing [tex]a=76m^2[/tex]

We know that density of air [tex]d=1.29kg/m^3[/tex]

Speed at top surface [tex]v_2=290m/sec[/tex] and speed at bottom surface [tex]v_1=150m/sec[/tex]

According to Bernoulli's principle force is given by

[tex]F=A\times d\times \frac{v_2^2-v_1^2}{2}=76\times 1.29\times \frac{290^2-150^2}{2}=3019632N[/tex]

samueladesida43

The lift in newtons due to Bernoulli's principle on a wing of area 76 m² is 3019632N.

How to calculate lift force?

According to this question, the following information are given:

  • Area of the wing = 76m²
  • Density of air = 1.29kgm³
  • Speed at the top surface (V2) = 290m/sec
  • Speed at the bottom surface (V1) = 150m/sec

According to Bernoulli's principle, force is given by the following expression:

F = A × d × V2 - V1/2

Where;

  • F = force
  • A = area
  • d = density

F = 76 × 1.29 × (290² - 150²)/2

F = 98.04 × 30800

F = 3019632N

Therefore, the lift in newtons due to Bernoulli's principle on a wing of area 76 m² is 3019632N.

Learn more about lift at: https://brainly.com/question/26168065

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