Answer: -2359 Joules
Explanation:
According to first law of thermodynamics:
[tex]\Delta E=q+w[/tex]
[tex]\Delta E[/tex]= Change in internal energy = -2886 J
q = heat absorbed or released = ?
w = work done or by the system
w = work done by the system=[tex]-P\Delta V[/tex] {Work is done by the system as the final volume is greater than initial volume and is negative}
w = -527 J
q = ?
[tex]-2886=q+(-527)[/tex]
[tex]q=-2359J[/tex] {Heat released by the system is negative}
Thus the amount of heat released by the system and carried away by the cooling system is -2359 Joules
According to first law of thermodynamics:
= Change in internal energy = -2886 J
q = heat absorbed or released = ?
w = work done or by the system
w = work done by the system= {Work is done by the system as the final volume is greater than initial volume and is negative}
w = -527 J
q = ?
{Heat released by the system is negative}
Thus the amount of heat released by the system and carried away by the cooling system is -2359 JoulesAnswer:
Explanation:
