Answer:
f(x) = -x³ + (3/2)x² + (11/3)x + 3.
Step-by-step explanation:
Given, real zeroes of f(x) are -2, 1/2, 3.
⇒ f(x) = -(x+2)(x-1/2)(x-3). (- sign because given leading coefficient is negative)
⇒f(x) = -x³ + (3/2)x² + (11/3)x + 3.
as the real zeroes are fixed, only one such polynomial is possible.
