Answer:
[tex]V_{b}-V_{a} = -38.72[/tex]
Explanation:
Consider the axis diagram attached.
Given:
Ey = Ez = 0
Eₓ = - 4x N/C · m
Since electric field is in x direction, potential difference would be:
[tex]V_{b} - V_{a} =-\int\limits^{4.40}_{0} {E_{x} } \, dx[/tex]
Here we integrate between limits 0 and 4.40 which is distance between A and B along x-axis.
[tex]V_{b} - V_{a} = -4 \left[\begin{array}{ccc}\frac{x^{2} }{2} \end{array}\right]^{4.40}_{0}[/tex]
[tex]V_{b}-V_{a} = -4 (9.68)\\V_{b}-V_{a} = -38.72[/tex]
