contestada

A 1 500-kg car rounds an unbanked curve with a radius of 52 m at a speed of 12 m/s. What minimum coefficient of friction must exist between the road and tires to prevent the car from slipping? (g = 9.8 m/s^2 )

Respuesta :

Answer:

Coefficient of friction will be 0.2825

Explanation:

We have given mass of the car m = 1500 kg

Radius of curve r = 52 m

Velocity v = 12 m /sec

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

At unbanked road frictional force must be equal to centripetal force

So [tex]\mu mg=\frac{mv^2}{r}[/tex], here [tex]\mu[/tex] is coefficient of friction

So [tex]\mu =\frac{v^2}{rg}=\frac{12^2}{52\times 9.8}=0.2825[/tex]

So coefficient of friction will be 0.2825

Otras preguntas