Answer:
Step-by-step explanation:
) Assuming speed of vehicles along a stretch of highway is normally distributed, the normal distribution formula would be applied. It is expressed as
z = (x - u)/s
Where
x = speed of vehicles
u = mean speed
s = standard deviation
From the information given,
u = 75
s = 3.8
z = (62 - 75)/3.8 = - 3.42
2)the student performed better in the biology test because the spread of the scores is not wide and the student got just 1 below the mean.
3) Since the Intelligence quotients are normally distributed, the normal distribution formula would be applied. It is expressed as
z = (x - u)/s
From the information given,
u = 100
s = 15
a) Below 90
z = (90 - 100)/15 = - 0.67
From the normal distribution table, the corresponding probability is
0.2514
b) Above 130
z = (130 - 100)/15 = 2
From the normal distribution table, the corresponding probability is
0.9773. Therefore,
P(x greater than 130) = 1 - 0.9773 = 0.0227
c) Between 90 and 130. The probability would be
0.9773 - 0.2514 = 0.7259