Answer:
Explanation:
Given
Three blocks are placed over each other at a certain distance.
Center of gravity of each block is at distance of 0.5 L from one end of block.
First We consider block 1 and 2
Block 1 center of gravity will try to tumble the block 1 if center of gravity torque goes beyond 0.5 L of second block.
i.e. maximum distance up to which block 1 is placed over block 2 is [tex]x=0.5 L[/tex]
combined center of gravity of 1 and 2 is
Center of gravity [tex]x=\frac{0.5L+L}{2}=\frac{3L}{4}[/tex]
Now consider block 2 and 3
Combined center of gravity of block 1 and 2 will tumble over when their Center of gravity goes beyond edge of block 1
i.e. maximum value of [tex]d=\frac{3L}{4}[/tex]
(b) As the no of blocks increases center of gravity increases so maximum value of [tex]d\rightarrow \infty[/tex]
