The magnitude of the electric force between two protons is 2.30 x 10^-26 N. How far apart are they?
a) 0.0220 mb) 0.100 mc) 0.480 md) 0.000570 me) 3.10 m

Respuesta :

To solve this problem we will use the concepts given by Coulomb's law defined for force, said law is mathematically described as

[tex]F = \frac{kq_1 q_2}{r^2}[/tex]

Here,

k = Coulomb's constant

[tex]q_{1,2}[/tex]= Charge of two protons

r = Distance between them

F = Force

Our values are given as,

[tex]F =2.3*10^{-26} N[/tex]

[tex]q_1 =q_2 = 1.6*10^{-19} C[/tex]

[tex]k =9*10^9 Nm^2/C2[/tex]

Rearrenging to find the distance and replacing we have that

[tex]r^2=\frac{(9*10^9 )(1.6*10^{-19})^2 }{2.3*10^{-26} }[/tex]

[tex]r^2=10.01*10^{-3} m^2[/tex]

[tex]r =\sqrt{10.01*10^{-3} m^2}[/tex]

[tex]r = 0.100m[/tex]

Therefore the correct option is B.