Answer:
Explanation:
Given
Frequency of one of the tuning fork [tex]f_1=349\ Hz[/tex]
Suppose [tex]f_2[/tex] is the frequency of second tuning fork
Beat produced is the difference of frequency of two tuning forks
no of beats produced n=3 beats per second
[tex]|f_1-f_2|=3[/tex]
[tex]f_1-f_2=\pm 3[/tex]
[tex]349-f_2=\pm 3[/tex]
case 1
[tex]349-f_2=3[/tex]
[tex]f_2=346\ Hz[/tex]
case 2
[tex]349-f_2=-3[/tex]
[tex]f_2=352\ Hz[/tex]