Respuesta :
Answer: The mass of nitrogen gas that must be reacted is 1.4 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For ammonia:
Given mass of ammonia = 1.7 g
Molar mass of ammonia = 17 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of ammonia}=\frac{1.7g}{17g/mol}=0.1mol[/tex]
The chemical equation for the production of ammonia follows:
[tex]N_2+3H_2\rightarrow 2NH_3[/tex]
By Stoichiometry of the reaction:
2 moles of ammonia is produced by 1 mole of nitrogen gas
So, 0.1 moles of ammonia will be produced from [tex]\frac{1}{2}\times 0.1=0.05mol[/tex] of nitrogen gas
Now, calculating the mass of nitrogen gas from equation 1, we get:
Molar mass of nitrogen gas = 28 g/mol
Moles of nitrogen gas = 0.05 moles
Putting values in equation 1, we get:
[tex]0.05mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.05mol\times 28g/mol)=1.4g[/tex]
Hence, the mass of nitrogen gas that must be reacted is 1.4 grams
