The positive displacement x = 0.27 cm.
Explanation:
The formula to calculate displacement of a particle executing simple harmonic motion is given by,
x = A
s
i
n
(
ω
t
)
where x represents the displacement,
A represents the amplitude,
ω represents the angular frequency,
t represents the time.
Given, amplitude A = 3.43 cm, t = 1 / 2 = 0.5 s
x = A
s
i
n
(
ω
t
)
Since ω = 2πf,
x = 3.43 sin (2[tex]\times[/tex]3.14[tex]\times[/tex]50[tex]\times[/tex]0.5)
= 3.43 sin(157)
x = 0.27 cm.
