Answer:
24%
Explanation:
Given that :
a pharmacy stocks solution 'Q' in an 8oz concentrated bottle
Let the solution Q be = V
so (8oz × V%) ------ Equation 1
Consequently, the stock bottles are diluted with 16oz of distilled water to prepare 24oz of 8% solution 'Q' in a 1L glass beaker.
that means since 16oz is added to the previous concentration of 8oz which gives 24oz in 8% solution Q; we have
(24oz × 8%) ------ Equation 2
Equation equation 1 and 2 together; we have:
(8oz × V) = (24oz × 8%)
V = [tex]\frac {24 oz*8}{8 oz}[/tex]
V = 3 × 8%
V = 24%
∴ the concentration of the stock bottle = 24%
