Answer:
The correct answer is option C.
Step-by-step explanation:
Length of shoe box = l = 11 inches
Width of the shoes box = w = 6 inches
Height of the shoe box = h = 5 inches
Wrapping paper required t cover the shoe box will be equal to the total surface area of the shoe box.
Shoe box = Cuboid
Total surface area of the cuboid = 2(lw+wh+hl)
Total surface area of shoe box : T
[tex]T=2\times (11 inch\times 6 inch+6 inch\times 5 inch+5 inch\times 11 inch)[/tex]
[tex]=T = 302 inch^2[/tex]
Frank will need 302 square inches of wrapping paper to cover the shoe box.
