Respuesta :

Let [tex]b_1,b_2,\ldots,b_{20}[/tex] be the 20 marks of the boys, and [tex]g_1,g_2,\ldots,g_{10}[/tex] be the 10 marks of the girls.

We know that the global mean was 70, meaning that

[tex]\dfrac{b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}}{30}=70[/tex]

Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is

[tex]b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}=2100[/tex]

By the same logic, we work with the marks of the boys alone: we know the average:

[tex]\dfrac{b_1+b_2+\ldots+b_{20}}{20}=62[/tex]

And we deduce the sum of the marks for the boys:

[tex]b_1+b_2+\ldots+b_{20}=1240[/tex]

Which implies that the sum of the marks of the girls is [tex]2100-1240=860[/tex]

And finally, the mean for the girls alone is

[tex]\dfrac{860}{10}=86[/tex]