Answer:
y=101.9869
Step-by-step explanation:
Let n be equal to x:
[tex]y=31.8\times 1.06^n=31.8\times 1.06^x[/tex]
We calculate the value of n as the difference between the two years:
[tex]n=x=2010-1990\\\\n=x=20[/tex]
#We use [tex]symbolab.com[/tex] to plot our function and input the x value of n=x=20 to obtain a y output.
#From our graph, y has a value of 101.9869, hence, the programmer's salry in 2010 is predicted to be 101.9869
