Respuesta :
Explanation:
We know that relation between Gibb's free energy and temperature is as follows.
[tex]\Delta G = -RT ln K[/tex]
We are given that the value of [tex]\Delta G[/tex] is 1.7 kJ/mol.
And,
k = [tex]\frac{[product]}{[substrate]}[/tex]
= [tex]\frac{\text{[fructofuranose]}}{\text{[fructopyranose]}}[/tex]
Since, k = 0.50357 and temperature is equal to 298 K.
Therefore,
[tex]\frac{\text{[fructofuranose]}}{\text{[fructopyranose]}}[/tex] = 0.50357
so, [tex]\frac{\text{[fructofuranose]}}{\text{[fructopyranose]}}[/tex] + 1 = 1.50357
= [tex]\frac{\text{[total fructose solution]}}{\text{[fructopyranose]}}[/tex]
= [tex]\frac{1}{1.50357}[/tex]
= 0.665
Therefore, we can conclude that 0.665 fraction of the total fructose in solution is fructopyranose.
