Answer: The molarity of the malonic acid solution is 0.08335 M
Explanation:
[tex]H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O[/tex]
To calculate the molarity of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2C_3H_2O_4[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.
We are given:
[tex]n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL[/tex]
Putting values in above equation, we get:
[tex]2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M[/tex]
Thus the molarity of the malonic acid solution is 0.08335 M
