Respuesta :
Answer:
The final velocity of the composite object is 3.14 m/s.
Explanation:
Given that,
Mass of object 1, [tex]m_1=2.95\ kg[/tex]
Initial speed of object 1, [tex]u_1=5.02i\ m/s[/tex]
Mass of object 2, [tex]m_2=2.62\ kg[/tex]
Initial speed of object 2, [tex]u_2=-3.63j\ m/s[/tex]
The two objects stick together. The momentum of two objects before and after remains constant. Let V is the final velocity of the composite object. using the conservation of linear momentum as :
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\\V=\dfrac{2.95\times 5.02i+2.62\times (-3.63)j}{2.95+2.62}\\\\V=\dfrac{14.809i-9.5106j}{5.57}\\\\V=(2.65i-1.7j)\ m/s\\\\|V|=\sqrt{2.65^2+1.7^2} \\\\|V|=3.14\ m/s[/tex]
So, the magnitude of final velocity of the composite object is 3.14 m/s.
