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For a science experiment, you would like to use the Doppler effect to double the perceived frequency of a harmonica, from the 261.7-Hz tone (middle C) that it emits, to 493.9 Hz (B4 note).Calculate the speed the harmonica must have in order for a stationary observer to hear 493.9 Hz.

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lublana

Answer:

304.34 m/s

Explanation:

We are given that

Frequency of middle C=f=261.7 Hz

Frequency of B4 emit,f'=493.9 Hz

We have to find the speed of harmonica must have in order for a stationary observer to hear 493.9 Hz.

Speed of sound,v=343 m/s

We know that

[tex]f'=f(\frac{v+v'}{v})[/tex]

[tex]493.9=261.7(\frac{343+v'}{343})[/tex]

[tex]343+v'=\frac{493.9\times 343}{261.7}[/tex]

[tex]v'=\frac{493.9\times 343}{261.7}-343[/tex]

[tex]v'=304.34m/s[/tex]

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