Answer:
Explanation:
To solve this problem we have to take into account that the energy consumed per second is the power. Hence, by multipling the power and the time spent to arrive to the lab we obtain the total energy consumed.
But first we have to calculate the time
[tex]t_{1}=\frac{x}{v_{1}}=\frac{4km}{10\frac{km}{h}}=0.4h=0.4(3600s)=1440s\\t_{2}=\frac{x}{v_{2}}=\frac{4km}{3\frac{km}{h}}=1.3h=1.3(3600s)=4800s\\[/tex]
Now we use E=W*t for both times
[tex]E_{1}=t_{1}W_{1}=(1440s)(700W)=1008000J\\E_{2}=t_{2}W_{2}=(4800s)(290W)=1392000J\\[/tex]
A. Hence, by running the energy consumed is lower.
B.
E1=1008000J
E2=1392000J
C. Because the more intense exercise is made in a lower time in comparison with the less intense exercise, and higher the time, more energy is consumed.