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A simple harmonic oscillator oscillates with frequency f when its amplitude is A. If the amplitude is now doubled to 2A, what is the new frequency?

A) 2f

B) 4f

C) f

D) f/2

E) f/4

Respuesta :

adelekeademolu

Answer:

(C) f

Explanation:

For a simple harmonic oscillator in the form of a loaded spring, its frequency is given by

[tex]f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}[/tex]

where k is the spring constant and m is the mass of the load.

It is observed that the amplitude of the spring does not factor into this equation. Hence, the frequency is independent of the amplitude and remains the same.

The same applies to a simple pendulum whose frequency is given by

[tex]f = \dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}[/tex]

l is the length of the pendulum and g is the acceleration of gravity.

It is observed as well that the amplitude does not appear in the equation.

abidemiokin

The amplitude does not have any effect on the frequency of the spring. None of the options are correct.

The formula for calculating the frequency of simple harmonic motion is expressed according to the formula:

[tex]f=\frac{1}{2 \pi}\sqrt{\frac{k}{m} }[/tex]

k is the spring constant

m is the mass of the spring

According to the formula, we can see that the frequency depends on just the spring constant and the mass of the spring but not the amplitude. Hence the amplitude does not have any effect on the frequency of the spring.

Learn more here: https://brainly.com/question/20885248

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