Answer:
[tex]v=11.3 ms^{-1}[/tex]
Explanation:
According to question, a pitcher threw a baseball straight up at 35.8 meters per second.
Use the expression of the equation of motion.
v= u+at
Here, v is the final velocity.
Put [tex]a= g= -9.8 ms^{-2}[/tex], t= 2.50 s, [tex]u=35.8 ms^{-1}[/tex] and u = 0.
[tex]v= 35.8+ (-9.8)\times 2.50[/tex]
[tex]v=11.3 ms^{-1}[/tex]
Therefore, the velocity of ball after 2.50 s is [tex]v=11.3 ms^{-1}[/tex].
