Respuesta :
Answer:
Speed of the wind is [tex]= \sqrt{(\frac{s}{t_1})^2-(\frac{s}{t_1t})^2 }[/tex]
Explanation:
Given that,
airliner cover distance s, in time t1 between the cities faces opposite A and B
Let the speed of the wind be v
and the speed of the plain be [tex]v_p[/tex]
The speed of the plain is
[tex]v_p = \frac{s}{t}[/tex]
Time taken from one side is
= half distance travelled / (vp +v)
Time taken during A and B is
[tex]t_A_B = \frac{s/2}{s/t_1 +v}[/tex]
Time taken during B to A
[tex]t_B_A = \frac{s/2}{s/t_1 -v}[/tex]
Total timetaken by plane at the presence of wind
[tex]t = t_A_B + t_B_A[/tex]
[tex]t = \frac{s/2}{\frac{s}{t_1} + v} + \frac{s/2}{\frac{s}{t_1} -v}[/tex]
rearrange the equation to get v
[tex]v = \sqrt{(\frac{s}{t_1})^2-(\frac{s}{t_1t})^2 }[/tex]
Speed of the wind is [tex]= \sqrt{(\frac{s}{t_1})^2-(\frac{s}{t_1t})^2 }[/tex]
Speed of wind in flight time.
The city A located directly west of the city B and when there is no wind the airliner aircraft makes a roundtrip at a distance of between them which is the flight time of t1 and travels at the same speed in both directions. The strong steady and gusty winds are blowing from the western side.
Thus the answer is a flight will take a longer time. As the plane needs to travel in the direction of the flow of wind as per time.
- As per the question, the plane is traveling at the same speed in both directions and the stead winds are blowing from the western side to the eastern side
- Thus the airliner has the same speed as before and hence the taking roundtrip will take more time of t2.
- Thus the flight will be for a longer duration.
Learn more about the directly west of city B.
brainly.com/question/13408112.
