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public class Test { public static void main(String[] args) { try { method(); System.out.println("After the method call"); } catch (ArithmeticException ex) { System.out.println("ArithmeticException"); } catch (RuntimeException ex) { System.out.println("RuntimeException"); } catch (Exception e) { System.out.println("Exception"); } } static void method() throws Exception { System.out.println(1 / 0); } }

Respuesta :

Answer:

"ArithmeticException" is the correct answer for the above question.

Explanation:

Missing Information : The above question does not hold that "what is the output of the program".

  • The above question has a class that holds the two functions one function is the main function which calls the other function in a try-catch block.
  • The method function holds one run time exception which is 1/0 which is an arithmetic exception.
  • It can be handle by the help of an arithmetic class object which is defined in the first catch block.
  • Hence the print function of this catch is executed and prints "ArithmeticException".

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