Answer:
[tex]n_{C_6H_{10}}=0.03molC_6H_{10}[/tex]
Explanation:
Hello,
In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:
[tex]n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}[/tex]
Besides, the mass could be computed as well by using the molar mass of cyclohexene:
[tex]m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}[/tex]
Even thought, the volume could be also computed by using its density:
[tex]V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}[/tex]
Best regards.
Answer:
The theoretical yield of moles cyclohexene is 0.0288 moles
Explanation:
Step 1: Data given
Volume of cyclohexanol = 3 mL
Density cyclohexanol = 0.9624 g/mL
Molar mass of cyclohexanol = 100.158 g/mol
Sulfuric acid is in excess
Density of cyclohexene = 0.811 g/mL
Molar mass of cyclohexene = 82.143 g/mol
Step 2: The balanced equation
C6H12O + H2SO4 → C6H10 + H3O + HSO4
Step 3: Calculate mass cyclohexanol
Mass cyclohexanol = density cyclohexane * volume
Mass cyclohexanol = 0.9624 g/mL * 3mL
Mass cyclohexanol = 2.8872 grams
Step 4: Calculate moles cyclohexanol
Moles cyclohexanol = mass cyclohexanol / molar mass
Moles cyclohexanol = 2.8872 grams / 100.158 g/mol
Moles cyclohexanol = 0.0288 moles
Step 5: Calculate moles cyclohexene
For 1 mol cyclohexanol we need 1 mol H2SO4 to produce 1 mol cyclohexene
For 0.0288 moles cyclohexanol we'll have 0.0288 moles cyclohexene
The theoretical yield of moles cyclohexene is 0.0288 moles
