Answer:
4,186 Joules of Heat Released
Explanation:
When calculating Specific Heat, it is good to remember two formulas:
[tex]Q = Cp * m* Delta T[/tex]
And
[tex]Cp = \frac{Q}{m * Delta T}[/tex]
For this problem, we are using the first eqution to find the missing variable Q or the amount of joules released. The work would look like this:
[tex]Q = Cp * m * DeltaT\\Q = 4.186 J/g*C * 50g * (20-0)\\Q= 4.186 J/g*C * 50g * 20\\Q = 4,186 J\\[/tex]
Hope this Helps!
