Answer:
Step-by-step explanation:
The problem states that the equation of the line is in the form y=kx+b
Therefore k would be the slope. Recall slope formula: y1-y2/x1-x2
Plug points in and simplify to 8/5. Remember that this is k so plug into original equation: y=8/5x+b. (5,5) would be easier and you will get that b = -3.
Additionally, you can solve using SoE. Plug points in from both sets and get 5=5k+b and -19=-10k+b Now simplify and get 24=15k, simplify again to get k=8/5. Now use same steps as above to get that b=-3.
Your final equation should be y=8/5x-3.
Hope that helps you get a 100 on your RSM homework!
The equation of the form y = kx +b that passes through M (5, 5) and N (–10, –19) is y = 8 / 5 x - 3
A linear equation is represented as follows:
y = kx + b
where
Therefore, the equation that passes through M (5, 5) and N (–10, –19) is as follows:
k = -19 - 5 / -10 - 5 = -24 / - 15 = 24 / 15 = 8 / 5
Hence, let's find b using (5, 5)
5 = 8 / 5 (5) + b
5 - 8 = b
b = -3
Therefore, the equaion is as follows:
y = 8 / 5 x - 3
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