Answer:
a) Profit P = -70 that is a loss
b) break even time t = 15 units
Step-by-step explanation: Given that the equation
P(t) = t^2 − 13t − 30
Where P represents his profit (money made) over time t
a. Find P(5). That is, the profit made when time t = 5
P(5) = 5^2 - 13(5) - 30
P(5) = 25 - 65 - 30
P(5) = -70
This means that Mr bean is making a loss of 70 dollars as at time t of the day equal to 5
Mr. Bean will break even when his profit equals zero.
P(t) = t^2 − 13t − 30
P(0) = t^2 − 13t − 30 = 0
t^2 − 13t − 30 = 0
Factorizing the above equation will give us
(t -15)(t + 3)
t = 15 or -3
Since time t can't be negative, the time of break even will be 15 units
a) Profit P = -70 that is a loss
b) break even time t = 15 units
Since the equation is [tex]P(t) = t^2 - 13t - 30[/tex]
Here P means his profit (money made) over time t
a. So, the profit when the time t = 5
P(5) = [tex]5^2 - 13(5) - 30[/tex]
P(5) = 25 - 65 - 30
P(5) = -70
b. Now the break-even is
[tex]P(t) = t^2 - 13t - 30\\\\P(0) = t^2 - 13t - 30 = 0\\\\t^2 - 13t - 30 = 0[/tex]
(t -15)(t + 3)
t = 15 or -3
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