Step-by-step explanation:
Each roll has 6 possible outcomes, so two rolls have 36 possible sums. We can make a table showing what these sums are:
[tex]\left[\begin{array}{ccccccc}&\textbf{1}&\textbf{2}&\textbf{3}&\textbf{4}&\textbf{5}&\textbf{6}\\\textbf{1}&2&3&4&5&6&7\\\textbf{2}&3&4&5&6&7&8\\\textbf{3}&4&5&6&7&8&9\\\textbf{4}&5&6&7&8&9&10\\\textbf{5}&6&7&8&9&10&11\\\textbf{6}&7&8&9&10&11&12\end{array}\right][/tex]
Of the 36 sums, 10 are greater than 8, and 18 are odd.
P(A) = 10/36 = 5/18
P(B) = 18/36 = 1/2
