Answer:
The daily production rate is 191.6 ton/day
Explanation:
The first step that is required to be carried out is by determining the thermal input:
The thermal input can be calculated via the expression:
[tex]W_{in} = \dfrac{W_{out}}{n_{th}}[/tex]
[tex]W_{in} = \dfrac{600}{0.35}[/tex]
[tex]W_{in} = 1714 \ MW[/tex]
The feed rate is calculated as:
coal feed rate = [tex]1714*10^6 \ watt * \dfrac{3.412 \ Btu}{watt.hr }* \dfrac{lb}{12000 \ Btu}[/tex]
= 487347 lb/hr
The sulfur feed rate is :
= 487347 × 0.035
= 17057 lb/hr
Sulfur removal rate = 17057 × 0.9
= 15351 lb/hr
However, to determine the actual alkalinity; we have:
actual alkalinity = 1.15 × 239.57
= 275.5 lb . mol / hr
The total alkalinity is = [tex]275.5 \ lbmol/hr *\dfrac{100.09 \ CaCo_3}{lb mol \ CaCo_3}[/tex]
= [tex]27575 \ lb \ CaCo_3 / hr[/tex]
The limestone feed rate = [tex]\dfrac{27575}{0.95}[/tex]
= 29026 lb/hr
= [tex]29026 \ lb/hr * \dfrac{24 \ hr}{ 1\ day}*\dfrac{1 \ ton }{2000 \ lb}[/tex]
= 348.3 ton/day
Finally, the daily production rate = 0.55*348.3 ton/day
= 191.6 ton/day
