Answer:
second option
Step-by-step explanation:
Given the 2 equations
y = [tex]\frac{2}{3}[/tex] x + 2 → (1)
6x - 4y = - 10 → (2)
Substitute y = [tex]\frac{2}{3}[/tex] x + 2 into (2)
6x - 4([tex]\frac{2}{3}[/tex] x + 2) = - 10 ← distribute parenthesis and simplify left side
6x - [tex]\frac{8}{3}[/tex] x - 8 = - 10 ( multiply through by 3 to clear the fraction )
18x - 8x - 24 = - 30
10x - 24 = - 30 ( add 24 to both sides )
10x = - 6 ( divide both sides by 10 )
x = - 0.6
Substitute x = - 0.6 into (1) and evaluate for y
y = [tex]\frac{2}{3}[/tex] × - 0.6 + 2 = 2x × - 0.2 + 2 = - 0.4 + 2 = 1.6
One Solution is (- 0.6, 1. 6 )
