Answer:
Option (3)
Step-by-step explanation:
PB is a tangent and PV, PU are the secants drawn to the circle.
[tex]m(\widehat {VB})[/tex] = 60° and [tex]m(\widehat{BS})[/tex] = 30°
By theorem of tangent and secants,
"When a tangent and secant are drawn from a point outside the circle, then the measure of the angle formed is one half the difference of intercepted arcs."
m∠BPV = [tex]\frac{1}{2}[m(\widehat{BV}-m(\widehat{BS})][/tex]
m∠3 = [tex]\frac{1}{2}[60-30][/tex]
m∠3 = 15°
Therefore, Option (3) will be the answer.
