Respuesta :
Answer:
No; the slopes of segment LM and segment LN are not opposite reciprocals
Step-by-step explanation:
slope of LM: (2 - 0)/(2 - 0) = 1
slope of LN: (-1 - 0)/(2 - 0) = -1/2
Two lines are perpendicular when the multiplication of their slopes is equal to negative one, that is, they are opposite reciprocals. In this case:
slope of LM*slope of LN = 1*(-1/2) = -1/2
The correct option is
No; the slopes of segment LM and segment LN are not opposite reciprocals
- The calculation is as follows:
slope of LM: [tex](2 - 0)\div (2 - 0)[/tex] = 1
And,
slope of LN: [tex](-1 - 0)\div (2 - 0)[/tex]= [tex]-1\div 2[/tex]
Here two lines should be perpendicular at the time when the multiplication of their slopes is equalivalent to negative one.
So,
= slope of LM × slope of LN
[tex]= 1\times (-1\div 2)\\\\ = -1\div 2[/tex]
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