Answer:
For this case we know that [tex]\frac{2\pi}{3}= 120 degrees[/tex]. For this case we want to find:
[tex] arctan(tan(\frac{2\pi}{3}))[/tex]
Since the tan and arctan functions are inverse when we apply bth at the same time we got the identity function so then we got for this case:
[tex] arctan(tan(\frac{2\pi}{3})) = I(\frac{2\pi}{3}) = \frac{2\pi}{3}[/tex]
Step-by-step explanation:
For this case we know that [tex]\frac{2\pi}{3}= 120 degrees[/tex]. For this case we want to find:
[tex] arctan(tan(\frac{2\pi}{3}))[/tex]
Since the tan and arctan functions are inverse when we apply bth at the same time we got the identity function so then we got for this case:
[tex] arctan(tan(\frac{2\pi}{3})) = I(\frac{2\pi}{3}) = \frac{2\pi}{3}[/tex]
