Answer:
- 90 16-oz cases and 30 20-oz cases will maximize resin and time use
- 120 16-oz cases will maximize profit
Step-by-step explanation:
Let x represent the number of cases of 16-oz cups produced.
Let y represent the number of cases of 20-oz cups produced.
The limitation imposed by available production time is ...
x + y ≤ 15·8 = 120 . . . . maximum number of cases produced in a day
The limitation imposed by raw material is ...
14x +18y ≤ 1800 . . . . . maximum amount of resin used in a day
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The point of intersection of the boundary lines for these inequalities can be found using substitution:
14(120- y)+18y = 1800
4y = 120 . . . . . subtract 1680, simplify
y = 30
x = 120 -30 = 90
This solution represents the point at which production will make maximal use of available resources. It is one boundary point of the "feasible region" of the solution space.
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The feasible region for the solution is the doubly-shaded area on the graph of these inequalities. It has vertices at ...
(x, y) = (0, 100), (90, 30), (120, 0)
The profit for each of these mixes of product is ...
(0, 100): 25·0 +20·100 = 2000
(90, 30): 25·90 +20·30 = 2850 . . . . uses all available resources
(120, 0): 25·120 +20·0 = 3000 . . . . maximum possible profit
The family can maximize their profit by producing only 16-oz cups at 120 cases per day.
