Answer:
Colin has 8 sheets left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers = [tex]x[/tex]
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:
[tex]\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)[/tex]
Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.
[tex]\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)[/tex]
Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class
[tex]\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8[/tex]
So, the answer is:
Colin has 8 sheets left for his third class.