Respuesta :
Answer:
Velocity in still air is = 960 miles per hour
Velocity of wind = 230 miles per hour.
Step-by-step explanation:
The velocity when flying against the wind = 2920 / 4 = 730 miles per hour.
The velocity when flying with the wind = 7140 / 6 = 1190
Let the rate of jet in still Air = x
Let the rate of jet in wind = y
Therefore, velocity against wind = x-y and wind = x + y
x - y = 730
x + y = 1190
Add both equation, 2x = 1920
x = 960
Now find the value of “y” = 1190 – 960 = 230
Thus, velocity in still air is = 960 miles per hour
Velocity of wind = 230 miles per hour.
Answer:
Rate of jet in still air = 960 miles/ hr
Rate of the wind = 230 miles/ hr
Step-by-step explanation:
Let the speed of jet in still air = [tex]u[/tex] miles/hr
Let the speed of air = [tex]v[/tex] miles/hr
So, against the wind, the resultant speed = [tex](u-v)[/tex] miles/hr
And, with the wind, the resultant speed = [tex](u+v)[/tex] miles/hr
Distance traveled against the wind = 2920 miles
Time taken against the wind = 4 hrs
Formula for distance is:
[tex]\bold{Distance =Speed \times Time}[/tex]
[tex]2920 = (u-v)\times 4\\\Rightarrow u-v=\dfrac{2920}{4}\\\Rightarrow u-v=730\ miles/hr...... (1)[/tex]
Distance traveled with the wind = 7140 miles
Time taken against the wind = 6 hrs
[tex]\bold{Distance =Speed \times Time}[/tex]
[tex]7140 = (u+v)\times 6\\\Rightarrow u+v=\dfrac{7140}{6}\\\Rightarrow u+v= 1190 \ miles/hr...... (2)[/tex]
Adding (1) and (2):
[tex]2u = 1920\\\Rightarrow \bold{u = 960 miles/hr}[/tex]
Putting [tex]u[/tex] in (1):
[tex]960 -v = 730 \\\Rightarrow \bold{v=230\ miles/hr}[/tex]
Therefore, the answer is:
Rate of jet in still air = 960 miles/ hr
Rate of the wind = 230 miles/ hr
