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Suppose there are n independent trials of an experiment with k3 mutually exclusive​ outcomes, where pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this​ situation?

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Complete question :

Suppose there are n independent trials of an experiment with k > 3 mutually exclusive​ outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this​ situation?

Answer: Ei = nPi

Step-by-step explanation:

Since Pi represents the probability of observing the ith outcome

The number of independent trials n = k>3 :

Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.

Hence, Expected count (Ei) = probability of ith count * n

Ei = nPi

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The formula of an expected count is given by .

[tex]E_i=np_i[/tex]

Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes,

where pi represents the probability of observing the ith outcome.

The expected counts for each possible outcome are given by .

[tex]E_i=np_i[/tex]

Where, [tex]p_i[/tex] is the probability of observing the ith outcome

[tex]E_i[/tex] is the expected count of the ith outcome.

Learn more:https://brainly.com/question/15870634                                                          

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