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11. Benito and Tyler are painting opposite sides of the same fence that is 150 feet long. Tyler has already painted 19.5

feet of his side of the fence when

Benito starts painting. Tyler paints at a rate of 11 fumin, and Benito paints at a rate of 15 ft/min


a. About how long will it take for the two sides of the fence to have an equal number of feet painted


b. The painter who finishes first gets to rest while the other painter finishes. About how long will the painter who

finishes first get to rest?

Respuesta :

Answer:

(a) 4.875 minutes

(b) 1.86 minutes

Step-by-step explanation:

The length of fence = 150 feet.

Rate of painting by Tyler = 11ft/min

Rate of painting by Benito = 15ft/min

(a) Let after time t minutes  both have painted equal number of feet.

As Taylor has already painted 19.5 feet. So,

[tex]15t=19.5+11t[/tex]

[tex]\Rightarrow 4t=19.5[/tex]

[tex]\Rightarrow t=\frac{19.5}{4}[/tex]

[tex]\Rightarrow t=4.875[/tex] minutes.

(b)The length of fencs to be painted by Tylor=150-19.5=130.5 feet.

So. time taken by Tylor to finish the painting

[tex]=\frac{130.5}{11}=11.86[/tex] minutes.

Time taken by Benito to finish the painting

[tex]=\frac{150}{15}=10[/tex] minutes

Here, tome taken by Benito is less, so Benoto finishes first.

Benoto will get the time to rest for 11.86-10=1.86 minutes.

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