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Suppose that your boss must choose three employees in your office to attend a conference in Jamaica. Because all 17 of you want to go, he decides that the only fair way is to draw names out of a hat. What is the probability that you, Anna, and Kevin are chosen? Enter a fraction or round your answer to 4 decimal places, if necessary.

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MrRoyal

Answer:

[tex]P(You\ n\ Anna\ n\ Kevin) = \frac{1}{4913}[/tex]

Step-by-step explanation:

Given

[tex]Total\ Employees = 17[/tex]

[tex]To\ Select = 3[/tex]

Required

Determine the probability of selecting You, Anna and Kevin

Assuming the selection process is fair;

Each employee has a probability of;

[tex]Probability = \frac{1}{17}[/tex]

So:

[tex]P(You\ n\ Anna\ n\ Kevin) = P(You) * P(Anna) * P(Kevin)[/tex]

[tex]P(You\ n\ Anna\ n\ Kevin) = \frac{1}{17} * \frac{1}{17} * \frac{1}{17}[/tex]

[tex]P(You\ n\ Anna\ n\ Kevin) = \frac{1}{4913}[/tex]

The  probability that you, Anna, and Kevin are chosen is [tex]1\div 4913[/tex]

Calculation of the probability:

Since there is three employees in your office to attend a conference in Jamaica. And, Because all 17 of you want to go, he decides that the only fair way is to draw names out of a hat.

So, here the probability should be

[tex]= (1\div 17)^3\\\\= 1\div 4913[/tex]

learn more about probability here: https://brainly.com/question/15783859

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