Suppose Cosine (x) = negative one-third where StartFraction pi Over 2 EndFraction less-than-or-equal-to x less-than-or-equal-to pi. What is the value of tan(2x)?

Suppose Cosine x negative onethird where StartFraction pi Over 2 EndFraction lessthanorequalto x lessthanorequalto pi What is the value of tan2x class=

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Answer:

D!!

Step-by-step explanation:

got it right on edge 2020

The value of the tangent of angle 2x will be 2√8 / 7. Then the correct option is D.

What is trigonometry?

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The trigonometric equation is given below.

cos x = –1/3

Then the sin x will be given as,

sin x = √(1 – cos² x)

sin x = √(1 – (–1/3)²)

sin x = 2√2 / 3

Then the value of tan x will be,

tan x = sin x / cos x

tan x = –2√2 / 1

tan x = 2√2

Then the value of tangent of angle 2x will be

[tex]\tan 2x = \dfrac{2 \tan x}{1 - \tan ^2 x}\\\\\tan 2x = \dfrac{2 (-2\sqrt 2)}{1 - (-2\sqrt 2) ^2 }\\\\\tan 2x = \dfrac{-4\sqrt 2}{1 - 8 }\\\\\tan 2x = \dfrac{-4\sqrt 2)}{-7}\\\\\tan 2x = \dfrac{2\sqrt 8)}{7}[/tex]

Thus, the value of the tangent of angle 2x will be 2√8 / 7.

Then the correct option is D.

More about the trigonometry link is given below.

https://brainly.com/question/22698523

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