Q
ZOO
What is the equation in slope-intercept form of the line that passes through the points
(-6, 4) and (6, 10)?

Respuesta :

Answer:

[tex]y = \frac{1}{2} x+7[/tex]

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: [tex]\frac{y2-y1}{x2-x1}[/tex]

Given points: (-6, 4), (6, 10)

(-6, 4) = (x1, y1)

(6, 10) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

[tex]\frac{10-4}{6-(-6)}[/tex]

Simplify:

10 - 4 = 6

6 - (-6) = 6 + 6 = 12

[tex]\frac{6}{12}=\frac{1}{2}[/tex]

The slope is [tex]\frac{1}{2}[/tex].

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (6, 10)) into the equation and solve for b:

[tex]10 = \frac{1}{2}(6)+b[/tex]

10 = 3 + b

7 = b

The y-intercept is 7.

Now that we know the slope and the y-intercept, we can write the equation:

[tex]y = \frac{1}{2} x+7[/tex]