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Answer:
see attached
Step-by-step explanation:
The line of reflection has a slope of -1/2, so each image point will be on a line of slope 2 through the corresponding pre-image point. It may be easiest to count the grid squares between the pre-image point and the line, then again from the line to the location of the image point. Those distances will be the same.
The reflected image is shown in the first attachment.
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If you want to do this algebraically, the formulas for finding the reflected points are given in the second attachment. For the given line, these become ...
(x, y) ⇒ (4/5 + 3/5x -4/5y, 8/5 - 4/5x - 3/5y)
Example:
C(-3, -5) ⇒ ((4 +3(-3) -4(-5))/5, (8 -4(-3) -3(-5))/5) = (15/5, 35/5) = C'(3, 7)
