Given:
Mass of the runner (m) = 50 kg
Speed of the runner (v) = 2 m/s
Equation:
[tex] \rm KE = \dfrac{1}{2} mv^2[/tex]
Answer:
By substituting values in the equation, we get:
[tex] \rm KE = \dfrac{1}{2} \times 50 \times 2^2 \\ \\ \rm = \dfrac{1}{2} \times 50 \times 4 \\ \\ \rm = 25 \times 4 \\ \\ \rm = 100 \: J[/tex]
[tex] \therefore [/tex] Kinetic energy of the runner = 100 J
Answer:
Given,
mass(m)=50kg
velocity(v)=2m/s
kinetic energy(K.E.)=?
We know that K.E.=1/2mv2
KE=1/2×50×2^2
Explanation:
=1/2×200
=100 Joule
