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Answer:
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Explanation:
The overall charge on ClO3− is shown on the image attached to this answer. If we calculate the formal charges on each atom in the structure, we will notice that one oxygen atom has a formal charge of -1 while all other atoms have a formal charge of zero.
This gives the compound an overall charge of -1 as shown in the image attached to this answer. This is the correct Lewis structure for the compound ClO3− .

The molecule has a formal charge of -1 on all oxygen atoms, and +2 on the Cl atom.
When all the electrons of an atom are shared equally, the charge attained by the atom is known as a formal charge.
The formal charge can be calculated as:
Formal charge = valence electron - non-bonding electron - [tex]\rm \dfrac{bonding\;electron}{2}[/tex]
In the molecule, the formal charge of Oxygen = -1.
In the molecule, the formal charge of Chlorine = +2
The oxygen atom has 8 electrons, in which 2 are shared in the bond formation, and 6 electrons are valence electrons.
The chlorine atom has 7 valence electrons in which 6 electron pairs are shared with the oxygen atom, and 1 lone pair has been available with Cl.
The structure of [tex]\rm ClO_3^-[/tex] molecule has been given in the image attached. The image shows the available lone pairs and the bonding in the structure.
Thus, the molecule has a formal charge of -1 on all oxygen atoms, and +2 on the Cl atom.
For more information about the formal charge, refer to the link:
https://brainly.com/question/9847214
