Respuesta :
Answer:
a. 0.047 M
b. 0.6778 moles
c. 6.76 g/mol
Explanation:
The formula for osmotic pressure is:
- π = i*M*R*T
Where:
- i is the van't Hoff's factor (in this case is 1, because it is a non electrolyte solute)
- M is the molar concentration
- R is the ideal gas constant
- T is the temperature in Kelvin
a.) So we solve for M:
- 875 torr ⇒ 785/760 = 1.15 atm
- 25 °C ⇒ 25+273.16 = 298.16 K
- 1.15 atm = 1 * M * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
- M = 0.047 M
b.) We calculate the moles of solute, using the volume and molar concentration:
- 725 mL / 1000 = 0.725 L
- 0.047 M * 0.725 L = 0.6778 moles
c.) We calculate the molar mass, using the mass and the number of moles:
- 4.58 g / 0.6778 moles = 6.76 g/mol
A. The molar concentration of the solution is 0.047 M
B. The mole of the solute in the solution is 0.034 mole
C. The molar mass of the solute is 134.7 g/mol
A. Determination of the molar concentration of the solution.
Osmotic pressure (π) = 875 torr = 875 / 760 = 1.15 atm
Temperature (T) = 25 °C = 25 + 273 = 298 K
Van't Hoff's factor (i) = 1 (non-electrolyte)
Gas constant (R) = 0.0821 atm.L/Kmol
Molarity (M) =?
π = iMRT
1.15 = 1 × M × 0.0821 × 298
1.15 = M × 24.4658
Divide both side by 24.4658
M = 1.15 / 24.4658
M = 0.047 M
B. Determination of the mole of the solute.
Molarity = 0.047 M
Volume = 725 mL = 725 / 1000 = 0.725 L
Mole of solute =?
Mole = Molarity x Volume
Mole of solute = 0.047 × 0.725
Mole of solute = 0.034 mole
C. Determination of the molar mass of the solute
Mole of solute = 0.034 mole
Mass of solute = 4.58 g
Molar mass of solute =?
Molar mass = mass / mole
Molar mass of solute = 4.58 / 0.034
Molar mass of solute = 134.7 g/mol
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